5y^2+2y+1=0

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Solution for 5y^2+2y+1=0 equation:


Simplifying
5y2 + 2y + 1 = 0

Reorder the terms:
1 + 2y + 5y2 = 0

Solving
1 + 2y + 5y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.2 + 0.4y + y2 = 0

Move the constant term to the right:

Add '-0.2' to each side of the equation.
0.2 + 0.4y + -0.2 + y2 = 0 + -0.2

Reorder the terms:
0.2 + -0.2 + 0.4y + y2 = 0 + -0.2

Combine like terms: 0.2 + -0.2 = 0.0
0.0 + 0.4y + y2 = 0 + -0.2
0.4y + y2 = 0 + -0.2

Combine like terms: 0 + -0.2 = -0.2
0.4y + y2 = -0.2

The y term is 0.4y.  Take half its coefficient (0.2).
Square it (0.04) and add it to both sides.

Add '0.04' to each side of the equation.
0.4y + 0.04 + y2 = -0.2 + 0.04

Reorder the terms:
0.04 + 0.4y + y2 = -0.2 + 0.04

Combine like terms: -0.2 + 0.04 = -0.16
0.04 + 0.4y + y2 = -0.16

Factor a perfect square on the left side:
(y + 0.2)(y + 0.2) = -0.16

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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